# Having an issue with the sqrt() function in c program

 Adam Martin · September 22, 2015 Hey guys, listed below is my script. As the title says, when I compile the script it shows no errors, but when I execute it (as you can see if you execute it) the standard deviation is shown as sqrt(353.84) instead of actually putting the answer (which is 18.81).Note that when I do compile it I do use -lm.I am new to thenewboston, and to programming in general, so hello all! Cheers#include #include int main(void){//Input Datafloat X1,X2,X3,X4,X5;X1 = 60.00, X2 = 95.00, X3 = 73.00, X4 = 41.00, X5 = 84.00;//Output Datafloat Variance,Sum,SD, D1sqr, D2sqr, D3sqr, D4sqr, D5sqr, M,D1,D2,D3,D4,D5;M = (X1 + X2 + X3 + X4 + X5)/5.0;D1 = X1 - M;D2 = X2 - M;D3 = X3 - M;D4 = X4 - M;D5 = X5 - M;D1sqr = D1*D1;D2sqr = D2*D2;D3sqr = D3*D3;D4sqr = D4*D4;D5sqr = D5*D5;Sum = D1sqr + D2sqr + D3sqr + D4sqr + D5sqr;Variance = (D1sqr + D2sqr + D3sqr + D4sqr + D5sqr)/5.0;SD = sqrt(D1sqr + D2sqr + D3sqr + D4sqr + D5sqr)/5.0;//Scores//scanf("%f %f %f %f %f", &X1,&X2,&X3,&X4,&X5);//Mean Equation//scanf("(%f+%f+%f+%f+%f)/5.0 = %f",&X1,&X2,&X3,&X4,X5,M);//Deviation Scores//scanf("%f-M",X1);scanf("%f-M",X2);scanf("%f-M",X3);scanf("%f-M",X4);scanf("%f-M",X5);//Squared Deviation//scanf("%f*%f",D1,D1);scanf("%f*%f",D2,D2);scanf("%f*%f",D3,D3);scanf("%f*%f",D4,D4);scanf("%f*%f",D5,D5);//Sum//scanf("%f+%f+%f+%f+%f",D1sqr,D2sqr,D3sqr,D4sqr,D5sqr);//Variance//scanf("(%f+%f+%f+%f+%f)/5.0 = %f",D1sqr,D2sqr,D3sqr,D4sqr,D5sqr,Variance);//Standard Deviation//scanf("sqrt(Variance)");printf("Score \t-\t Mean \t=\t Deviation Score \t\tSquared Deviation\n");printf("(X)\t\t(M)\t\t(X-M)\t\t\t\t(X-M)squared\n");printf("%.2f\t\t%.2f\t\t%.2f\t\t\t\t%.2f\n",X1,M,D1,D1sqr);printf("%.2f\t\t%.2f\t\t%.2f\t\t\t\t%.2f\n",X2,M,D2,D2sqr);printf("%.2f\t\t%.2f\t\t%.2f\t\t\t\t%.2f\n",X3,M,D3,D3sqr);printf("%.2f\t\t%.2f\t\t%.2f\t\t\t\t%.2f\n",X4,M,D4,D4sqr);printf("%.2f\t\t%.2f\t\t%.2f\t\t\t\t%.2f\n",X5,M,D5,D5sqr);printf("\t\t\t\t\t\tSum: %.2f\n",Sum);printf("Variance: = %.2f/5 = %.2f\n",Sum,Variance);printf("Standard Deviation = SD = sqrt(%.2f)\n",Variance);return 0;}

## Replies

 Adam Martin · September 25, 2015 Hey Krootushas, I ended up figuring it out. I just changed printf("SD = %.2f\n",SD); and it resolved it. thank you for the reply!
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