Challenge #1

0 Harshad Lele · May 14, 2015
Hey ,

completed  #Challenge1

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

int main()
    char password[100];
    int i,a,b,c;

    printf("Enter your password : ");
    scanf( "%s" , &password);

    for (i= 0 ; i < strlen(password); i++ )
        if  ( isupper(password) )
        else if ( isdigit(password) )
        else if ( password== '$' )
                c =1;
        if (a == 1 && b == 1 && c == 1)
        printf("Your password is Good");
        printf("your password sucks");

     return 0;

if this the optimized way of doing it? Can it get better? 

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0 Nishad Samant · May 16, 2015
This code is not going to work, the logic you are using needs to check each character of the password individually... and not the entire string together....use that hint...and rewrite the code again
0 c student · May 17, 2015
@Nishad Samant  If you haven't looked closely enough, he has actually placed in the index of his array.  You can tell because the text is italicized from where you'd expect it to be.  The page has read the index as part of its formatting.
0 Nishad Samant · May 17, 2015
The functions isupper() isdigit() etc are used to check the characters passed, here he is passing the entire will not work...he has to index each character of the string indicidually
0 c student · May 17, 2015
Have you actually tried reading what I wrote before typing that?
0 Reynaldo Gunawan · May 18, 2015
Hi, I tried to do this challenge but I can't seem to get the code right and make the program work the way i want it. Can someone please take a look and maybe spot the mistakes that i made? That would be cool.
0 Harshad Lele · May 18, 2015
@ c student - thank you yes my code got changed due to page formatting :)
@ Nishad - Yes I have did the exact thing you said in the post, thanks :)
@ Reynaldo - declare int i outside the for loop. You can not declare new variable inside the for loop. Also use char array. as identifying of  '$' can not be done using int array. Hope this helps :)
0 Reynaldo Gunawan · May 19, 2015
@Harshad i will keep that in mind. Thanks for your reply
0 Akshay Pimpalkar · May 22, 2015
@harshad thumbs up for your code...

i have a problem...if i deliberately enter a password without a lower case letter , then it is not showing error(i.e"your message sucks")......however it has to show error.

According to my code, i have included check for lower case letter and message corresponding to it, but it is not displaying error in the output when there is an absence of lower case letter. rather it is showing that "your password is perfect", which should not happen.

Your code is also not showing the same...what do you think? what should we do?
0 Superman HC · May 24, 2015
Sorry for the previous incomplete code...
Here is the code again:


int main(){
int j=0;
char pass[10];
int upper=0, lower=0, digit=0, sc=0;

printf("Enter your password:\n");

while(j!=' '){
else if(isdigit(pass[j])){
     printf("Password must contain atleast one upper case, one lower case, one digit and a special character");
    printf("Good to go");
0 Kandy Naz · May 27, 2015
hey friends, can you please check this code and let me know what is wrong
# include <stdio.h>
# include <stdlib.h>
# include <ctype.h>
# include <string.h>
# include <math.h>

int main ()


int password[10];
int i;
int lower, upper, digit, dollar =0;
printf (" enter your password\n");
scanf (" %c ",password);

for(i =1 ; i <= 10; i++)

if (isalpha(password))
if( isupper (password))

else if (isdigit(password))
digit ++;

} // for loop

if (lower && digit && upper && dollar)
printf ( "your password is strong and proceed further");
printf (" Bad Password, check your rules again !!");

return 0;

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