# Python Challenge #1

 Brock Cryoston · October 15, 2014 2 lines, I think this is the most compact way of doing the challenge.In Bucky's tutorial #9 he mentioned that if you add a 3rd number in the parentheses it will count in increments of 4.

## Replies

 Windy Boja · October 19, 2014 Hi  The problem is that the way u did it, it means that the result starts from 0 and Buckys asked to choose numbers from 1 to 100. If u put 1 the point where tha program should start, it still will not work correctly because it will be incremented by 4 so u will have numbers 5 and so on (5, 9 etc..) I did it this way and it seems to work ok Brock Cryoston · October 20, 2014 Oh I didn't catch that part darn! Thanks Jose Peregrina · October 21, 2014 Brock, your approach it is really nice despite you do not use x%4. It can be done as follows:``for d in range(1,101,4): print(d+3)``You will get from 4 to 100. Daniel Bogorad · October 31, 2014 hy ,and yet another way, no real difference though ...``for n in range(1, 101):    if n%4 is 0:        print(n)`` Vaibhav Patel · November 11, 2014 magicNumber = 0for n in range(26):    if n is magicNumber:        print(n)        break    else:        print(n*4) Vaibhav Patel · November 11, 2014 16:37:31for n in range(0, 26):           if n is 0:              print(n)          else:              print(n*4) Vaibhav Patel · November 11, 2014 Another way to get the result.Bucky, Please have you say on all the above comments as well.I have come up with 3 different way to get the result, but not sure if any of them is correct way.for n in range(1, 26):    if n  > 0:        print(n*4)Can't think any more... Abom in81on · November 13, 2014 I used for n in range(1,101):    if n % 4 is 0:        print(n)which I think meets all the criteria set out in the challenge and works correctly in the most efficient way. I'd like to see if anyone has a better way to do this.And thanks for the challenge Bucky, it's a good check to make sure I'm picking this up.edit* The white space hasn't copied correctly so the indentation is a little off.
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## Python

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